Rectangle Overlap Problem & Solution
An axis-aligned rectangle is represented as a list [x1, y1, x2, y2], where (x1, y1) is the coordinate of its bottom-left corner, and (x2, y2) is the coordinate of its top-right corner.
Its top and bottom edges are parallel to the X-axis, and its left and right edges are parallel to the Y-axis.
Two rectangles overlap if the area of their intersection is positive. To be clear, two rectangles that only touch at the corner or edges do not overlap.
Given two axis-aligned rectangles rec1 and rec2, return true if they overlap, otherwise return false.
See the rectangle overlap problem on LeetCode.
C++ Solution
#pragma GCC optimize("Ofast")
#pragma GCC optimization("unroll-loops")
#pragma GCC target("avx,avx2,fma")
static const int _=[](){std::ios::sync_with_stdio(false);cin.tie(nullptr);cout.tie(nullptr);return 0;}();
class Solution {
public:
bool isRectangleOverlap(vector<int>& rec1, vector<int>& rec2) {
int x1 = rec1[0];
int y1 = rec1[1];
int x2 = rec1[2];
int y2 = rec1[3];
int x3 = rec2[0];
int y3 = rec2[1];
int x4 = rec2[2];
int y4 = rec2[3];
// Tests if the second rectangle is to the left, right, top, or bottom of the first.
return !(y4 <= y1 || y2 <= y3 || x2 <= x3 || x4 <= x1);
}
};