Maximum Depth of N-ary Tree Problem & Solution

Given a n-ary tree, find its maximum depth.

The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.

See the maximum depth of n-ary tree problem on LeetCode.

C++ Solution

#pragma GCC optimize("Ofast")
#pragma GCC optimization("unroll-loops")
#pragma GCC optimization("max-inline-insns-recursive-auto")

static const int _=[](){ios::sync_with_stdio(false);cin.tie(nullptr);cout.tie(nullptr);return 0;}();

/*
class Node {
public:
  int val;
  vector<Node*> children;

  Node() {}

  Node(int _val) {
    val = _val;
  }

  Node(int _val, vector<Node*> _children) {
    val = _val;
    children = _children;
  }
};
*/
class Solution {
public:
  int maxDepth(Node* root) {
    if (root == nullptr) {
      return 0;
    }

    int depth = 0;
    for (int i = 0; i < root->children.size(); ++i) {
      depth = max(depth, maxDepth(root->children[i]));
    }

    return depth + 1;
  }
};

Start Here

Many paths, there are. Follow yours, you must.