Binary Tree Preorder Traversal Problem & Solution
Given the root
of a binary tree, return the preorder traversal of its nodes' values.
See the binary tree preorder traversal problem on LeetCode.
C++ Solution
#pragma GCC optimize("Ofast")
#pragma GCC optimization("max-inline-insns-recursive-auto")
static const int _=[](){std::ios::sync_with_stdio(false);cin.tie(nullptr);cout.tie(nullptr);return 0;}();
/**
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
vector<int> preorderTraversal(TreeNode* root) {
vector<int> traversal;
preorderTraversal(root, traversal);
return traversal;
}
private:
void preorderTraversal(TreeNode* node, vector<int>& traversal) {
if (node == nullptr) {
return;
}
traversal.push_back(node->val);
preorderTraversal(node->left, traversal);
preorderTraversal(node->right, traversal);
}
};