Binary Tree Paths Problem & Solution
Given the root
of a binary tree, return all root-to-leaf paths in any order.
A leaf is a node with no children.
See the binary tree paths problem on LeetCode.
C++ Solution
#pragma GCC optimize("Ofast")
#pragma GCC optimization("max-inline-insns-recursive-auto")
static const int _=[](){std::ios::sync_with_stdio(false);cin.tie(nullptr);cout.tie(nullptr);return 0;}();
/**
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
vector<string> binaryTreePaths(TreeNode* root) {
vector<string> results;
binaryTreePaths(root, "", results);
return results;
}
private:
void binaryTreePaths(TreeNode* root, string result, vector<string>& results) {
if (root == nullptr) {
return;
}
if (root->left == nullptr && root->right == nullptr) {
result += to_string(root->val);
results.push_back(result);
}
string tmp = result + to_string(root->val) + "->";
binaryTreePaths(root->left, tmp, results);
binaryTreePaths(root->right, tmp, results);
}
};